So for illustration of my problem I have created a simple view consisting of 1 column.
I apply filter thus : Views.ZZ_List.NormalizedName = 'Java 6 Update 11'
and wonderfully this results in 1 row which shows the value 'Java 6 Update 11'
However, in reality, I want this filter to return all rows with the string 'Java' in it.
So in traditional SQL : Like '%Java%' (or Like '*Java*')
In Information Steward, I see that there is no 'Like' statement.
Hence, reading online, I tried this one : match_regex(Views.ZZ_List.NormalizedName, 'Java', null)
Yet after applying the above, I get zero rows returned.
Also tried :
match_pattern(Views.ZZ_List.NormalizedName, 'Java')
match_pattern(Views.ZZ_List.NormalizedName, '*Java*')
.... and may I say, many more variations.
Please can someone point out what the proper way of achieving a 'like' functionality is ?
Many Thanks
